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For the time period ofinterest, there is a $10^{-4}$ {\em a priori} chance of this happening, andHolmes has installed a burglar alarm to try to forestall this event.  Thealarm is 95\% reliable in sounding when a burglary happens, but also has afalse positive rate of 1\%.  Holmes' neighbor, Watson, is sure (well, say 90\%sure) to call Holmes at his office if the alarm sounds, but he is also a bit ofa practical joker, and knowing Holmes' concern, might (30\%) call even if thealarm is silent.  Holmes' other neighbor, Mrs. Gibbons, is a well-known lushand often befuddled, but Holmes believes that she is four times more likely tocall him if there is an alarm than if not.\end{quotation}\subproblem{Building the model (4 pts)}Draw a Bayes network that describes the above dependencies.  Now define aBayes net, {\tt Holmes}, that models this.  Think carefully about theprobabilistic dependencies and exactly what they mean.  Turn in a listing ofthe call to {\tt define-bnet} that defines your network.You will have noticed that the story above does not tell the actual conditionalprobability that Gibbons will call if the alarm sounds or that she will call ifthe alarm is silent.  Indeed, these probabilities would be quite difficult forHolmes to estimate.  Fortunately, it is only the likelihood ratio betweenthese conditions that matters.  You can verify that your choice or particularnumbers to use for the conditional probabilities leading to Gibbons' call areimmaterial so long as their ratio is $4$. \subproblem{Calculations (2 pts)}Within a few minutes of each other, Holmes is phoned by both Watson and Gibbons.Use your network to calculate the probability that Holmes has suffered aburglary.\subproblem{Explaining away (3 pts)}Realizing that Holmes lives in Los Angeles, it occurs to us that there might beanother explanation for the (probable) alarm at Holmes' house.  If asufficiently large earthquake occurs, it may set off the burglar alarm evenwithout there being a burglary.  Define a new Bayes net, {\tt quake}, based onthe same facts that you used for {\tt holmes}, but with the followingadditional story:\begin{quotation}Holmes, always the anxious type, listens to KNX, ``News Radio,'' while at work,which will report, with 95\% reliability, the occurrence of a sufficientlylarge quake.  Holmes thinks that a burglary and an earthquake can each set offhis burglar alarm in independent ways that make {\em noisy-or} a good model. From his original belief about the probabilistic connection between burglaryand alarm, Holmes can compute a causal probability from burglary to alarm and aleak probability for an alarm occurring in the absence of a burglary.  Heestimates the probability of a quake causing an alarm as 60\%.  The incidenceof quakes in Los Angeles is equal to the incidence of burglaries.\end{quotation}Use the {\tt quake} network to calculate the probability of Holmes' househaving been burgled if he receives calls from Watson and Gibbons, but alsohears the report of a quake on KNX.\subproblem{Multiple connections (3 pts)}\begin{quotation}Holmes realizes that his daughter was planning to visit his house this day, andwould surely (98\%) call if she heard the alarm, unless she was convinced thatit was really the earthquake that had set it off.\end{quotation}Build another variation of the {\tt quake} network, {\tt daughter}, in which youmodel the daughter's calling or not calling.  Describe and justify themodeling assumptions that you make, and the numbers you choose.  ({\em Hint:}There is no single right answer here; choose a reasonable model of this part ofthe story and justify it.)If she does {\em not} call, what is the probability that Holmes' house has infact been burgled.  Explain how this relates to the answer from the {\tt quake}network.\problem{Probabilistic diagnosis}Consider the diagnostic domain {\tt dom3} of Problem Set 6, reproducedand shown graphically in Figure \ref{bpg}.\begin{figure}[tb]\begin{center}\parbox[t]{3in}{%\begin{tabular}{cc}{\tt\begin{tabular}[b]{l}(define dom3\\\ \ (make-domain\\\ \ \ '((a s1 s2 s5)\\\ \ \ \ \ (b s1 s2 s4)\\\ \ \ \ \ (c s1 s3 s4 s5)\\\ \ \ \ \ (d s1 s5)\\\ \ \ \ \ (e s2 s3 s4)\\\ \ \ \ \ (f s5)\\\ \ \ \ \ (g s3 s4)\\\ \ \ \ \ (h s3 s5)\\\ \ \ \ \ )))\end{tabular}}}\hfil\parbox[b]{3in}{\begin{tabular}[t]{c}\scaledpicture {3.71in} by {4.47in} (bpg scaled 750)\end{tabular}}%\end{tabular}\end{center}\caption{A bipartite graph for a diagnostic problem corresponding to domain{\tt dom3} of Problem Set 6.  Disorders are letters, symptoms are $s_i$, andnumbers on arcs between diseases and symptoms are the causal probabilities.  Weassume independent causation (i.e., noisy-or) combination of causal influencesat each symptom, with a uniform leak probability of 0.05.} \label{bpg}\end{figure}\subproblem{Defining a bipartite graph Bayesian problem (3 pts)}Use {\tt define-bnet} (much as it is used in defining {\tt mcbn2} in {\ttexamples.scm}) to define the network corresponding to the diagnostic domain{\tt dom3} with the additional probabilistic information shown in Figure\ref{bpg}.  Turn in a listing of the expression you use to define this net.\subproblem{Exploring absent symptoms (2 pts)}Use the program you wrote for computing conditional probabilities to compute theprobability of disease {\tt a} given that symptoms {\tt s1}, {\tt s2} and {\tts3} are present.Now compute the probability of {\tt a} given that those symptoms are presentbut that {\tt s4} and {\tt s5} are absent.  If the answer differs from theprevious one, why?  Contrast this behavior with the treatment that set-coverdiagnosis gives to {\em absent} symptoms.\subproblem{Joint probabilities of multiple diseases (2 pts)}Calculate, as above, the probability of disease {\tt e} assuming only thatsymptoms {\tt s1}, {\tt s2} and {\tt s3} are present.Calculate, similarly, the probability of disease {\tt h} under the samecondition.Ben Bitdiddle (remember {\em him}?) suggests that the probability that{\tt a}, {\tt e} and {\tt h} are present together is just theproduct of the probabilities that each is present by itself (as you've justcomputed).  Check his suggestion by computing the joint probability of thesethree diseases given that symptoms {\tt s1}, {\tt s2} and {\tt s3} arepresent.  Comment on the sagacity of Ben's advice.\subproblem{Use for diagnosis (3 pts)}Assuming that {\tt s1}, {\tt s2} and {\tt s3} are present and {\tt s4} and{\tt s5} are absent, find the most likely set of diseases.  You should not needto explore the $2^8$ possibilities, if you think about which sets seem likepromising candidates, and if you are willing to take a slight risk of missingthe very best.  {\em Hint:} We do not expect you to write a program to do this,but just to explore ``by hand'' the most likely sets of diseases.\problem{Grand Synthesis}\subproblem{Design (3 pts)}Describe a general solution to the previous subproblem (findingthe most likely set of diseases to explain the presence/absence of a set ofsymptoms).  You should find the set-cover algorithm and our code here to bevery useful.\subproblem{Implementation (Extra Credit of 5 pts)}Implement the design you sketched in the preceding subproblem.  You probably needto build both a domain (in the lingo of ps6) and a Bayes net for the samedisease-symptom relationships, unless you redefine {\tt causes} and {\ttconsequences} to work off the Bayes net data structures directly.  Debuggingyour code will be difficult because of the circular data structures and theconsequent problems of printing out.  Note the useful procedures in {\ttdebug.scm} to help ameliorate, but not solve, this problem.Show your program and demonstrate it on the above example.  Does it get thesame solution that you did?  Why, or why not?\end{document}